(2.3L * 313K)/ 298K = 2.42L
the volume of gas at 3.5 atm is 300ml .if tlhe preasure is increased to 5atm.what will be the new volume?
V1 (initial volume) = 300 ml V2 (final volume) = ? unknown
P1 (initial pressure) = 3.5 atm P2 (final pressure = 5 atm
This problem can be solved using Boyle's Law which state that volume is inversely proportional to pressure when the temperature and the amount of gas are constant.
Boyle's Law formula is P1V1 = P2V2
To find V2 we can use V2 = P1V1 / P2
V2 = P1V1 / P2
= 3.5 atm × 300 ml / 5 atm (cancel the unit atm)
= 1050 ml / 5
V2 = 210 ml
The final volume is 210 ml
Hope it helps=)
The volume of gas at 3.5 atm is 300ml .If tlhe preasure is increased to 5 atm. What will be the new volume ?
We have the following information:
P1 (initial pressure) = 3.5 atm
V1 (initial volume) = 300 mL
P2 (final pressure) = 5 atm
V2 (final volume) = ? (in ml)
We have an isothermal transformation, that is, its temperature remains constant, if the pressure of a gas increases, then its volume decreases, since it is known that the pressure and the volume of a gas are inversely proportional. Applying the data to the formula of Boyle's Law, we have:
The new volume is 210 ml